(4-i)^2-(1+2)^2=0

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Solution for (4-i)^2-(1+2)^2=0 equation: 



(4-i)^2-(1+2)^2=0

We add all the numbers together, and all the variables

(-1i+4)^2-3^2=0

We add all the numbers together, and all the variables

(-1i+4)^2-9=0

We move all terms containing i to the left, all other terms to the right

(-1i+4)^2=9

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